How do you calculate the RMS value for a square wave with peak-to-peak voltage of 4V and a 2V DC offset? - rms voltage of a square wave with dc offset
AC RMS does not mean DC
Square wave 50% duty cycle means that half of the peak to peak
C
Tuesday, February 9, 2010
Rms Voltage Of A Square Wave With Dc Offset How Do You Calculate The RMS Value For A Square Wave With Peak-to-peak Voltage Of 4V And A 2V DC Offset?
Subscribe to:
Post Comments (Atom)
2 comments:
RMS means root instead of the mean (average). 4 Move the Vpp square wave voltage (2 half the time, and -2 means half) with a V 2 4 volts, half the time, and zero volts, half the time. 4 squared is 16, and 0 square is equal to zero, so that the same time (on average, a cycle or a whole number of cycles) which is two (16 +0) / 2 = 8. Take the square root of 8 for the RMS value.
So, this heat wave, when a resistance of 2828 volts DC, which shows how the value of the wave.
--
Regards,
John Popelish
The RMS (Root Mean Square) value of a periodic wave is a direct measure of the heat in a resistive load.
Vrms = √ (1 / T) [∫ ∫ dt V1 + V2 ² ² .. dt + ∫ dt Vn ²]
Based on a 50% tariff, and the DC offset is is always present,
Vrms = √ (1 / 1 sec [(4 V) ² (1 / 2 sec) + (0 V) ² (1 / 2 sec)])
Vrms = √ (8)
Vrms = 2.828 V
EDIT:
Roger JPopelish and I apologize. It is 2.82 Vrms. They had the right answer. I am very ashamed of my lazing on a simple question. JPopelish posted the first correct answer.
I understood the question correctly) (and its waveform. I had balanced the waveform to 4 VDC. Worse, I have the same leg of mathematics, with a 4 VDC compensate for the effective voltage √ 20, or 4.47 V (not √ 10).
The link leads to the "good" waveform think the question.
http://www.saguaro.net/answers/waveform. ...
Post a Comment